30% w/v H2SO4 means 30 g H2SO4 in 100 ml solution. Mass of H2SO4 = 30 g Density of H2SO4 = 1.05 g/ml Volume of H2SO4 = Mass/Density = (30 g)/(1.05g/ml) = 28.57 ml Volume of solution = 100 ml Density of solution = 1.5 g/ml Mass of solution = Volume*Density = (100 ml)*(1.5 g/ml) = 150 […]
In KMnO4, oxidation state of Mn is +7. As the oxidation state of atom increases, the element become more electronegative in nature. Mn gain 5 electron in acidic medium and reduces to +2 oxidation state. Gain of 5 electron shows that the electronegativity of Mn has increased. Therefore, KMnO4 is a good oxidizing agent. Note:
Why KMnO4 act as a good oxidizing agent in acidic medium? Read More »
Question: If E° for copper electrode is +0.34 V, how will you calculate its emf value when the solution in contact with it is 0.1 M in copper ions? How does emf for copper electrode change when concentration of Cu2+ ions in the solution is decreased? Solution: The emf of an electrode when dipped in
E° for copper electrode is +0.34 V, how will you calculate its emf value? Read More »
Molar conductivity increases with increase in volume and when volume increases the concentration of solution decreases (because no.of ions in the solution decrease) which makes the solution dilute. On dilution when concentration approaches zero, the molar conductivity is known as limiting molar conductivity. In case of strong electrolytes the ionisation is easy and
How can you determine limiting molar conductivity for strong and weak electrolyte? Read More »
Solution: Given, [A]=0.1 mol L-1, [B]=0.2 mol L-1, k = 2.0×10-6 mol-2 L2 s-1Rate =k[A][B]2 = (2.0x 10-6 ) x (0.1 mol L-1) x (0.2 mol L-1) 2 = 8.0 x 10-9 mol-2 L2 s-1. The concentration of A is reduced to (0.1 – 0.06) = 0.04 mol L-1.Now according to the equation 1 mole of A reacts with 2 mole of B. So, 0.04
Calculate the initial rate of reaction. Read More »
Let x g of each gas is mixed. Molar mass of ethane = 30 g/mol Molar mass of hydrogen = 2 g/mol Mole = Given mass/Molar mass Moles of ethane = (x/30) mol Moles of hydrogen = (x/2) mol So, the fraction of total pressure exerted by hydrogen
Amine is a type of compound that is derived from ammonia, i.e., NH3. We can simply say, that amines are derivatives of ammonia. We study about amines in Organic Chemistry, and they are basically classified as functional groups or organic nitrogen compounds that contain a nitrogen atom with a lone pair. Generally, in amines, hydrogen
Distinguish b/w ethyl amine and diethyl amine? Read More »
Thermodynamics is the study of flow of heat between system and surrounding. It deals with energy changes accompanying all types of physical and chemical processes. Thermodynamics helps to lay down the criteria for predicting feasibility or spontaneity of a process, including a chemical reaction, under a given set of conditions. It also helps to determine
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Solution: Bond angle is inversely proportional to electronegativity of substituents. i.e., Electronegativity of side atom increase then the bond angle (X-P-X) decreases. So, X-P-X or F-P-F bond angle is least in POF3. That’s why the O-P-F is maximum. Hence, the correct order of bond angle for O-P-X in the given molecules
What is the correct order of bond angle for O-P-X in the given molecules? Read More »
