In this post, we will discuss about the halogenation of alkane with a previous year question based on it. What is the halogenation of alkane? A halogenation reaction is a chemical reaction between a substance and a halogen in which one or more halogen atoms are incorporated into molecules of the substance. Halogenation of an […]
Simple Halogenation of alkane Read More »
In this post, we will discuss about Dalton’s Atomic Theory. Dalton based his theory on two laws: the law of conservation of mass and the law of constant composition. The law of conservation of mass says that matter is not created or destroyed in a closed system. That means if we have a chemical reaction, the amount
What is Dalton’s Atomic Theory? Read More »
Quantum numbers are fundamental concepts in quantum mechanics that play a crucial role in understanding the behavior of electrons in atoms. For students preparing for competitive exams such as JEE and NEET, a solid grasp of quantum numbers is essential for mastering topics related to atomic structure and electron configurations. In this blog post, we
Quantum numbers: Bonus Concept with 25 Questions Read More »
Compound X has the molecular formula C4H10O2. X has an unbranched carbon chain and contains two OH groups. On reaction with an excess of hot alkaline potassium permanganate X is converted into a compound of molecular formula C4H6O4.To which two carbon atoms in the chain of X are the two OH groups attached?A. 1st and
Compound X has the molecular formula C4H10O2. Read More »
This question is word problem of organic chemistry. The question is provided below: Each of the compounds below is treated separately with excess NaBH4. The product of each reaction is then heated with excess concentrated H2SO4. In each case, one or more products are formed with molecular formula C7H10. Which compounds give only one final product with the molecular
Word Problem based question Read More »
Law of multiple proportions states that if two elements form more than one compound, then the ratios of the masses of the second element which combine with a fixed mass of the first element will always be ratios of small whole numbers. This law is sometimes called Dalton’s Law, named after John Dalton, the chemist who first expressed it. 2.66 g chloride
Law of multiple proportions Read More »
We are given with, Molarity = 0.001 M Volume = 100 ml = 0.1 L Number of moles of H2SO4 = Molarity*Volume = 0.001 M*0.1 L = 0.0001 mole Dissociation of sulphuric acid occurs as: H2SO4 ⟶ 2H+ + SO42- From the above equation, 1 molecule H2SO4 given 1 SO42- ion then,
Calculate the number of sulphate ions in 100 ml of 0.001 M H2SO4 solution. Read More »
Given mass of CO2 = 200 mg = 0.2 g Molar mass of CO2 = 44 g/mol Number of moles of 200 mg CO2 = Given mass/Molar mass of CO2 = 0.2 g/44 g mol-1 = 0.00454 mole Number of molecules of CO2 removed = 1021 Number of moles of CO2 removed = 1021/(6.022*1023) =
From 200 mg of CO2, 10^21 molecules are removed. How many moles of CO2 are left? Read More »
Q. Assertion : The element having with electronic configuration 1s2 2s2 2p6 3s2 and 1s2 2s2 belong to the same group Reason: Both have same number of electrons in the valence shell Solution: Elements having same number of valence shell are present in same group. Here, each elements have 2 valence electrons.
Assertion-Reason based electronic configuration Read More »
30% w/v H2SO4 means 30 g H2SO4 in 100 ml solution. Mass of H2SO4 = 30 g Density of H2SO4 = 1.05 g/ml Volume of H2SO4 = Mass/Density = (30 g)/(1.05g/ml) = 28.57 ml Volume of solution = 100 ml Density of solution = 1.5 g/ml Mass of solution = Volume*Density = (100 ml)*(1.5 g/ml) = 150
